The Official Journal of the Pan-Pacific Association of Input-Output Studies (PAPAIOS)

# Table 18 System SYS1scr: Specification

 $\mathrm{d}\left({\mathrm{sca}}_{1}\right)=\mathrm{c}\left(1\right)+\mathrm{c}\left(2\right)\ast {\mathrm{sca}}_{1}\left(-1\right)+\mathrm{c}\left(501\right)\ast \mathrm{d}90$ $\mathrm{d}\left({\mathrm{sca}}_{2}\right)=\mathrm{c}\left(3\right)+\mathrm{c}\left(4\right)\ast {\mathrm{sca}}_{2}\left(-1\right)+\mathrm{c}\left(5\right)\ast \mathrm{d}\left({\mathrm{sca}}_{2}\left(-1\right)\right)+\mathrm{c}\left(502\right)\ast \mathrm{d}95+\mathrm{c}\left(503\right)\ast \mathrm{d}96$ $\mathrm{d}\left({\mathrm{sca}}_{3}\right)=\mathrm{c}\left(6\right)+\mathrm{c}\left(7\right)\ast {\mathrm{sca}}_{3}\left(-3\right)+\mathrm{c}\left(8\right)/\mathrm{t}+\mathrm{c}\left(504\right)\ast \mathrm{d}96$ $\mathrm{d}\left({\mathrm{sca}}_{4}\right)=\mathrm{c}\left(9\right)+\mathrm{c}\left(10\right)\ast {\mathrm{sca}}_{4}\left(-2\right)+\mathrm{c}\left(11\right)\ast \mathrm{d}\left({\mathrm{sca}}_{4},2\right)+\mathrm{c}\left(12\right)\ast \mathrm{t}/\left(\mathrm{t}+1\right)+\mathrm{c}\left(505\right)\ast \mathrm{d}99$ $\mathrm{d}\left({\mathrm{sca}}_{5}\right)=\mathrm{c}\left(13\right)+\mathrm{c}\left(14\right)\ast {\mathrm{sca}}_{5}\left(-1\right)+\mathrm{c}\left(15\right)\ast \mathrm{d}\left({\mathrm{sca}}_{5}\left(-1\right)\right)+\mathrm{c}\left(16\right)\ast \mathrm{t}/\left(\mathrm{t}+1\right)$ $\mathrm{d}\left({\mathrm{sca}}_{6}\right)=\mathrm{c}\left(17\right)+\mathrm{c}\left(18\right)\ast {\mathrm{sca}}_{6}\left(-1\right)+\mathrm{c}\left(19\right)\ast \mathrm{d}\left({\mathrm{sca}}_{6}\left(-1\right)\right)+\mathrm{c}\left(20\right)\ast \mathrm{t}/\left(\mathrm{t}+1\right)$ $\mathrm{d}\left({\mathrm{sca}}_{7}\right)=\mathrm{c}\left(21\right)+\mathrm{c}\left(22\right)\ast {\mathrm{sca}}_{7}\left(-1\right)+\mathrm{c}\left(23\right)\ast \mathrm{d}\left({\mathrm{sca}}_{7}\left(-1\right)\right)+\mathrm{c}\left(24\right)\ast \mathrm{d}\left({\mathrm{sca}}_{7}\left(-2\right)\right)$ $+\mathrm{c}\left(25\right)\ast \mathrm{d}\left({\mathrm{sca}}_{7}\left(-3\right)\right)+\mathrm{c}\left(26\right)\ast \mathrm{t}/\left(\mathrm{t}+1\right)$ $\mathrm{d}\left({\mathrm{sca}}_{8}\right)=\mathrm{c}\left(27\right)+\mathrm{c}\left(28\right)\ast {\mathrm{sca}}_{8}\left(-1\right)+\mathrm{c}\left(29\right)\ast \mathrm{d}\left({\mathrm{sca}}_{8},2\right)+\mathrm{c}\left(506\right)\ast \mathrm{d}96$ $\mathrm{d}\left({\mathrm{sca}}_{9}\right)=\mathrm{c}\left(30\right)+\mathrm{c}\left(31\right)\ast {\mathrm{sca}}_{9}\left(-1\right)+\mathrm{c}\left(32\right)\ast \mathrm{d}\left({\mathrm{sca}}_{9}\left(-2\right)\right)+\mathrm{c}\left(33\right)\ast \mathrm{t}/\left(\mathrm{t}+1\right)+\mathrm{c}\left(507\right)\ast \mathrm{d}96$ $\mathrm{d}\left({\mathrm{sca}}_{10}\right)=\mathrm{c}\left(34\right)+\mathrm{c}\left(35\right)\ast \mathrm{t}/\left(\mathrm{t}+1\right)+\mathrm{c}\left(36\right)\ast {\mathrm{sca}}_{10}\left(-1\right)+\mathrm{c}\left(508\right)\ast \mathrm{d}90+\mathrm{c}\left(509\right)\ast \mathrm{d}95$ $\mathrm{d}\left({\mathrm{sra}}_{1}\right)=\mathrm{c}\left(37\right)+\mathrm{c}\left(38\right)\ast {\mathrm{sra}}_{1}\left(-1\right)+\mathrm{c}\left(39\right)\ast \mathrm{d}\left({\mathrm{sra}}_{1}\left(-2\right)\right)+\mathrm{c}\left(40\right)/\mathrm{t}+\mathrm{c}\left(510\right)\ast \mathrm{d}98$ $\mathrm{d}\left({\mathrm{sra}}_{2}\right)=\mathrm{c}\left(41\right)+\mathrm{c}\left(42\right)\ast {\mathrm{sra}}_{2}\left(-1\right)+\mathrm{c}\left(43\right)\ast \mathrm{d}\left({\mathrm{sra}}_{2},2\right)+\mathrm{c}\left(511\right)\ast \mathrm{d}99$ $\mathrm{d}\left({\mathrm{sra}}_{3}\right)=\mathrm{c}\left(44\right)+\mathrm{c}\left(45\right)\ast {\mathrm{sra}}_{3}\left(-2\right)+\mathrm{c}\left(46\right)\ast \mathrm{d}\left({\mathrm{sra}}_{3}\left(-1\right)\right)+\mathrm{c}\left(512\right)\ast \mathrm{d}99$ $\mathrm{d}\left({\mathrm{sra}}_{4}\right)=\mathrm{c}\left(47\right)+\mathrm{c}\left(48\right)\ast {\mathrm{sra}}_{4}\left(-1\right)+\mathrm{c}\left(513\right)\ast \mathrm{d}96+\mathrm{c}\left(514\right)\ast \mathrm{d}91$ $\mathrm{d}\left({\mathrm{sra}}_{5}\mathrm{HP}\right)=\mathrm{c}\left(49\right)+\mathrm{c}\left(50\right)\ast {\mathrm{sra}}_{5}\mathrm{HP}\left(-1\right)+\mathrm{c}\left(51\right)\ast \mathrm{d}\left({\mathrm{sra}}_{5}\mathrm{HP}\left(-1\right)\right)$ $\mathrm{d}\left({\mathrm{sra}}_{5}\mathrm{HPd}\right)=\mathrm{c}\left(52\right)\ast {\mathrm{sra}}_{5}\mathrm{HPd}\left(-1\right)+\mathrm{c}\left(53\right)\ast \mathrm{d}\left({\mathrm{sra}}_{5}\mathrm{HPd}\left(-1\right)\right)+\mathrm{c}\left(515\right)\ast \mathrm{d}93+\mathrm{c}\left(516\right)\ast \mathrm{d}96$ $\mathrm{d}\left({\mathrm{sra}}_{6}\right)=\mathrm{c}\left(54\right)+\mathrm{c}\left(55\right)\ast {\mathrm{sra}}_{6}\left(-1\right)+\mathrm{c}\left(56\right)\ast \mathrm{d}\left({\mathrm{sra}}_{6},2\right)+\mathrm{c}\left(517\right)\ast \mathrm{d}93$ $\mathrm{d}\left({\mathrm{sra}}_{7}\right)=\mathrm{c}\left(57\right)+\mathrm{c}\left(58\right)\ast {\mathrm{sra}}_{7}\left(-2\right)+\mathrm{c}\left(59\right)\ast \mathrm{d}\left({\mathrm{sra}}_{7},2\right)+\mathrm{c}\left(60\right)/\mathrm{t}$ $\mathrm{d}\left({\mathrm{sra}}_{8}\mathrm{HP}\right)=\mathrm{c}\left(61\right)+\mathrm{c}\left(62\right)\ast {\mathrm{sra}}_{8}\mathrm{HP}\left(-1\right)+\mathrm{c}\left(63\right)\ast \mathrm{d}\left({\mathrm{sra}}_{8}\mathrm{HP},2\right)+\mathrm{c}\left(518\right)\ast \mathrm{d}93+\mathrm{c}\left(519\right)\ast \mathrm{d}94$ $\mathrm{d}\left({\mathrm{sra}}_{8}\mathrm{HPd}\right)=\mathrm{c}\left(64\right)\ast \mathrm{d}\left({\mathrm{sra}}_{8}\mathrm{HPd},2\right)+\mathrm{c}\left(520\right)\ast \mathrm{d}92+\mathrm{c}\left(521\right)\ast \mathrm{d}95$ $\mathrm{d}\left({\mathrm{sra}}_{9}\right)=\mathrm{c}\left(65\right)+\mathrm{c}\left(66\right)\ast {\mathrm{sra}}_{9}\left(-1\right)+\mathrm{c}\left(522\right)\ast \mathrm{d}93+\mathrm{c}\left(523\right)\ast \mathrm{d}99$ $\mathrm{d}\left({\mathrm{sra}}_{10}\mathrm{l}\right)=\mathrm{c}\left(67\right)+\mathrm{c}\left(68\right)\ast {\mathrm{sra}}_{10}\mathrm{l}\left(-3\right)+\mathrm{c}\left(524\right)\ast \mathrm{d}94$